Abstract
We show distributional results for the length of the longest matching consecutive subsequence between two independent sequences A1, A2,..., Am and B1, B2,..., Bn whose letters are taken from a finite alphabet. We assume that A1, A2,... are i.i.d. with distribution μ and B1, B2,... are i.i.d. with distribution ν. It is known that if μ and ν are not too different, the Chen-Stein method for Poisson approximation can be used to establish distributional results. We extend these results beyond the region where the Chen-Stein method was previously successful. We use a combination of 'matching by patterns' results obtained by Arratia and Waterman [1], and the Chen-Stein method to show that the Poisson approximation can be extended. Our method explains how the matching is achieved. This provides an explanation for the formulas in Arratia and Waterman [1] and thus answers one of the questions posed in comment F19 in Aldous [2]. Furthermore, in the case where the alphabet consists of only two letters, the phase transition observed by Arratia and Waterman [1] for the strong law of large numbers extends to the distributional result. We conjecture that this phase transition on the distributional level holds for any finite alphabet.
| Original language | English (US) |
|---|---|
| Pages (from-to) | 139-159 |
| Number of pages | 21 |
| Journal | Combinatorics Probability and Computing |
| Volume | 5 |
| Issue number | 2 |
| DOIs | |
| State | Published - 1996 |
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